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ITC544 IT Fundamentals  

Pages : 2 | Type : Essay

Answers: 1. a). (152)x= (6A)16 x = ? 6A is in hexadecimal, the decimal representation will be 6 * 161 + 10 * 160 = 96 + 10 = 106 in decimal 152 is with base x, the decimal representation will be 1 * x2 + 5 * x1 + 2 * x0 x2 + 5x + 2 in decimal Therefore, x2 + 5x + 2 = 106 x2 + 5x – 104 = 0 x2 + 13x – 8x – 104 = 0 (x + 13)(x – 8) = 0 x = 8, x = -13 As the value of base can...

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userWritten By : Mark     postPosted On : May 08, 2020     downloadDownload : 0
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ITC544 IT Fundamentals 3  

Pages : 2 | Type : Essay

Answers: 1. (a): Firstly, let covert hexadecimal Number (6A) to equivalent decimal number. =(6A) 16                                                         &nb...

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userWritten By : Mark     postPosted On : May 30, 2020     downloadDownload : 0

More Courses from Charles Sturt University

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ITC544-Logic Diagram Of A Combinational Circuit  

Pages : 2 | Type : Essay

Answers: 1.(152)x= (6A)16   X2+ (5 * X1) + (2 * X0) = (6 * 161) + (10 * 160) X2 + 5X + 2 = 106 X2 + 5X  - 104 = 0 X2 + 13X  - 8X – 104 = 0 X(X + 13) – 8(X + 13) = 0 (X - 8) (X + 13) = 0 X = 8 and X = -13 So, the value of X is 8 Conversions BED16to base 3 BED = (B * 162) + (E * 161) + (D * 160) = 2816 + 224 + 13 =305310 (3053)10 =   BED16 =>  (11012002)3 3217into 2-...

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userWritten By : Mark     postPosted On : Jul 10, 2020     downloadDownload : 0
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ITC544 Assessment Item 1  

Pages : 3 | Type : Essay

Answer: Introduction to Computer organization and Architecture Which of the following characteristics meets the criteria for Assembly language? It is the easiest language that can be used for writing programs It does not needs to be translated to the machine language It use the alphabetic codes instead of binary number for the machine language None of the above Explanation: it is a low level language used for microprocessor and repre...

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userWritten By : Mark     postPosted On : Jul 13, 2020     downloadDownload : 0
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ITC544-Computer Organization And Architecture | Capacity Of A Disk Driver  

Pages : 3 | Type : Essay

Answer: 1.Capacity of the drive can be calculated using the formula Capacity C = Surfaces x Tracks x Sectors x Bytes = 23 x 512 x 64 x 32 = 24117248 = 23 Gb The formula used for the calculation of the rotational delay is given below Rotation delay = ½ x [(60 /RPM) x (1000 /1 Sec)] = ½ x [(60 /9600) (1000)] = 6.25 /2 = 3.125 milliseconds The Access Time is calculated using the formula Access time = Seek time + laten...

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userWritten By : Mark     postPosted On : Jul 23, 2020     downloadDownload : 0
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ITC544-Data Representation And Digital Logic  

Pages : 3 | Type : Essay

Answers: 1.Determine the value of base xif (152)x = (6A)16   Firstly, let covert hexadecimal Number (6A) to equivalent decimal number.  (6A) 16                                              &...

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userWritten By : Mark     postPosted On : Jul 28, 2020     downloadDownload : 0
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ITC544-Discussion On The Computer Organization And Architecture  

Pages : 2 | Type : Essay

Answers: 1.a) Let us consider the base to be Y, Given, (152) Y = (6A) 16  Or, Y2 + 5Y + 2*Y = 6*16 + A Or, Y2 + 5Y + 2*Y = 6*16 + 10 Y2 + 5Y + 2 = 106 Y2 + 5Y- 104 = 0 Y2 + 13Y- 8Y – 104 = 0 Y (Y + 13) – 8(Y + 13) = 0 (Y - 8) (Y + 13) = 0 Y = 8 and Y = -13 Hence, the value of Y is 8. The value of the base is 8.    b)Conversions: i) BED16converting to base-3 = B * 16*16 + ...

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userWritten By : Mark     postPosted On : Aug 25, 2020     downloadDownload : 0
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ITC544-Discusssion On MARIE And ISA Program  

Pages : 3 | Type : Essay

Answers: 1.a. MARIE program for the calculation of Fib(n) where user inputs = n is given below: ORG 100 Input Input number Store N // Input from the user is taken for printing the number of terms Store Ctr // It is used for storing the variable of the counter to the accumulator Loop1, Clear Load Ctr // The valu of the counter is loaded to the processor from the accumulator Subt C1 // A substraction is done with the value of C1 Store Ct...

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userWritten By : Mark     postPosted On : Aug 31, 2020     downloadDownload : 0

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