In a school assembly, a placard was shown as in the figure given, in which ABC is a quadrant of a circle and a semicircle is drawn with BC as diameter. Each section of the placard has depicted virtues like: (I) Hard work, (ll) Honesty and (III) Punctuality written on it boldly. How much area been given to honesty.What area has been allotted to hard work (use ?e=227)
Area of triangle ABC,
(Punctuality) = (1/2×70×70) cm2
= 2450 cm2
Area of quadrant ABC,
(Punctuality + Honesty)
= (22/7×70×70×1/4) cm2
= 3850 cm2
Therefore, Area for honesty,
= (3850 - 2450) cm2
= 1400 cm2
Area of Honesty + Hard work,
= 22/7× (70√2)2×1/2
= 15400 cm2
Therefore, Area for Hard work,
= 15400 – 1400 = 14000 cm2 Ans.
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