Question 1
a)![]()
Figure 1: Histogram of MVPA of Overweight and non-overweight Australian university students
From the histograms we find that they are right skewed. Hence the mean MVPA of the overweight the respondents is less than median value. Similarly the mean MVPA of non-overweight respondents is less than median value.
b)
To analyse the distribution of MVPA according to overweight the independent sample t-test is used. In the present analysis there are two unrelated groups – overweight and non-overweight. The overweight classification is the independent variables. We analyse the difference in overweights dependence on MVPA. MVPA is dependent variable.
c)
Null Hypothesis The mean MVPA of overweight respondents is equal to the mean MVPA of non-overweight respondents
Alternate Hypothesis The mean MVPA of overweight respondents is not equal to the mean MVPA of non-overweight respondents
The test is carried out at a = 0.05
Thus if p-value for the test is less than a then accept Null Hypothesis else reject Null Hypothesis.
For overweight persons the mean MVPA is 3.397345 and standard deviation is 3.048872
For non- overweight persons the mean MVPA is 3.716766 and standard deviation is 2.639543
The total number of respondents is 300.
Thus df = 298.![]()
Textbox 1: results of independent sample t-test
From the test results we find that p-value = 0.3653. Since p-value is more than0.05, level of significance. Hence, we reject Null Hypothesis.
Thus there is no difference in mean MVPA between overweight and non-overweight respondents.
Question 2
To analyse the research question the most appropriate test in the paired sample t-test. A paired sample t-test is used to analyse the difference in means of two variables which are related. In the present questions the respondent’s weight at enrolment and at graduation are compared. Since the variables weight at enrolment and at graduation is related through respondents hence the paired sample t-test / dependent sample t-test is used.
Question 3
a)![]()
Textbox 2: 95% CI of GPA of overweight and non-overweight students
The 95% confidence interval for the difference in mean GPA between overweight and non-overweight is 0.03989531, 0.46413733.
b) When another sample of the Australian university students is taken and the mean GPA of non-overweight students is 4.846707 and mean GPA of overweight students is 4.594690, then with 95% confidence it can be said that the mean difference of the sample would lie between 0.03989531 and 0.46413733.
c) From the calculation of 95% CI of mean GPA for overweight and non-overweight students it would be difficult to tell whether the results are statistically significant. Just from the results of 9% CI we do-not know the sample size, neither do we know the mean and standard deviation of the mean difference.
Question 4
The difference in means of the groups is 0.5.
The standard deviation of the groups = 0.9
Hence, the signal / noise ratio = 0.5/0.9 = 0.556
Thus, for signal / noise ratio of 0.556, with power = 0.8 and a = 0.05 the sample size required can be calculated as:
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Textbox 3: Analysis of the required sample size
Thus the minimum sample size required in each group is 43 to detect a difference of 0.5 in mean GPA having standard deviation of 0.9, power = 0.8 and a = 0.05.
Question 5
a)
Table 1: Crosstabulation of frequency of Gender vs Overweight
|
Gender
|
Overweight
|
Male
|
Female
|
Not-overweight
|
98
|
69
|
Overweight
|
36
|
77
|
Table 2: Crosstabulation of row percentages of Gender vs Overweight
|
Gender
|
|
|
Overweight
|
Male
|
Female
|
Total
|
Count
|
Not-overweight
|
58.7
|
41.3
|
100
|
167
|
Overweight
|
31.9
|
68.1
|
100
|
113
|
b)
From looking at the table of frequency or percentage it would be difficult to tell if there is any relationship between gender and overweight.
From the tables we find that while the percentage of non-overweight males is higher than females, the percentage of males who are overweight is less than the percentage of females.
Similarly the percentage of Non-overweight males is higher than overweight males. On the other hand the percentage of non-overweight females is lower than overweight females.
c)
The requirements of Chi-square tests are met –
- Both the variables are nominal variables.
- The sample size of both the groups under study is different
- The distribution of the sample size is skewed.
d)
Null Hypothesis: There is no association between Gender and OverWeight.
Alternate Hypothesis: There is an association between Gender and Overweight
Degrees of freedom = 1
Decision Rule : If the p-value is less than 0.05 then we accept the Null Hypothesis.
![]()
Textbox 4: Pearson’s Chi-square test
From the above textbox we find that c2 = 19.433. The p-value is less than 0.001 at a=0.05. Hence we accept the Null Hypothesis. Thus there is no association between Gender and Over weight
Question 6
The sample proportion that is overweight = 0.4
The margin of error = 0.1
The confidence interval = 0.95%![]()
Textbox 5: Calculation for sample size
Thus for a population proportion of 40% at 95% CI a minimum sample size of 93 is required to achieve a 10% margin of error for the survey of overweight Australia university students.