1.
Consider triangle ABC shown above.
Let P be the half plane of line AB in which point C lies, let K be the half plane of line BC in which point A lies, and let L be the half plane of line CA in which point B lies. By definition, the interior domain of the triangle ABC is the intersection P ∩ K ∩ T.
Using Hilbert’s Proposition, there exists a point D lying between A and B. using the same reasoning, there exists a point E lying between C and D. claiming that E ∈ P ∩ K ∩ T, which is the interior of triangle ABC. Indeed, point E lies in the same half plane P of line AB as point C. Indeed, the segment EC lies entire in P since D ∗ E ∗ C. The points B, D and E lie in the same half plane T of line CA. Indeed, because of A ∗ D ∗ B and D ∗ E ∗ C, segments DB and DE lie entirely in T.
Similarly, since segments AD and DE lie in the half plane K, we see that points A, D and E lie in the same half plane K of line BC.
2.
Let assume that S is a convex having the two points A and B being in S
Lemma
If S is convex, T is convex, and then S ∩ T is convex
Let be a half plane bounded by the line
Let A and b be two points in the plane.
For any point P in the plane such that P the point (1 – t)P + tQ is in T
Note that A and B are on the same side of the line.
Let T be an element of the line segment AB
If A = T, then T is in half plane
If B = T, then T is in half plane
Thus every point T is an element of segment AB in.
The is a convex set
3..
The interior of triangle is always a convex set
Proof:
Denote the triangle as , and the interior of the boundary of as int()
From boundary of polygon is Jordan curve, it follows that the boundary of is equal to imag of a Jordan curve, so int() is well defined.
Denote the vertices of as A1, A2, A3 for i , put j = 1mod3 +1, k = (i + 1)mod3 +1, and:
Ui = {Ai +st(Aj – Ai)+(1 – s)t(Ak – Ai): s(0..1), t
Suppose that Ai is an integral in it follows from definition of polygon that Ai cannot be zero or straight. Then Ai is larger than a straight angle, which is impossible by sum angles of triangle equals two right angles.
It follows that Ai is convex
From characterization of interior of triangle, it follows that
Int() = i
From interior of convex angle is convex set, it follows for that Ui is a convex set.
4.
Figure A and C
Figure A
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The sequence of drawing will be
A-B-C-DA-E-C
Figure C
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The sequence of drawing A-B-C-D-A-E-F-C-G-D-F