Nuts
|
Cost of purchasing (Rand/kg)
|
Material available (Kg)
|
Almonds
|
1200
|
400
|
Cashew
|
1060
|
200
|
Peanuts
|
280
|
600
|
Walnuts
|
840
|
300
|
As given in question,
In a pack of Delux mix the amount of almond cashew is Xa and Xc, … Xr respectively
Similarly in companion mix, the amount of almond, cashew and raisins will be as a, c, p,w,r
One again suppose the package of Delux mix is D and companion mix be C
Our objective function will
Minimise (Total Cost) = Cost of almond + Cost of Cashew + Cost of Peanut + Cost of Walnut + Cost of raisins
Now I have to formulate LP. This is as follows.
Cost(Z) = Xa*D +Xc(Dc +Cc)+Xp*Dp+Xw(Dw+Cw)+Ir*Cr
The constraints are stated in excel file, which is as follows
General constraint
a<=400
|
c+x<=200
|
p<=600
|
w+y<=300
|
For delux Mix
a>=0.1(a+b+c+d)
|
c>=0.1(a+b+c+d)
|
p>=0.1(a+b+c+d)
|
w>=0.1(a+b+c+d)
|
(a+b)>=0.5*(a+b+c+d)
|
p<=0.2(a+b+c+d)
|
(a+b+c+d)>=(4000*0.1)
|
For companion Mix
x>=0.1(x+y+z)
|
x>=0.3(x+y+z)
|
x>=0.4(x+y+z)
|
z>=0.2*(x+y+z)
|
(x+y+z) >=(5000*0.1)
|
After setting and running the solver we get the following result
Cell
|
Name
|
Original Value
|
Final Value
|
|
$B$8
|
Total Cost(Z) Cost of purchasing (Rand)
|
482000
|
482000
|
|
Cell
|
Name
|
Original Value
|
Final Value
|
Integer
|
$E$3
|
Cashew Companion mix
|
120
|
120
|
Contin
|
$E$5
|
Walnuts Companion mix
|
180
|
180
|
Contin
|
$E$6
|
Unlimited Companion mix
|
200
|
200
|
Contin
|
The optimum purchasing plan for deluxe given below
Nuts
|
Cost of purchasing (Rand)
|
Material avaialable (Kg)
|
Delux mix
|
Companion mix
|
Almonds
|
1200
|
400
|
120
|
|
Cashew
|
1060
|
200
|
80
|
120
|
Peanuts
|
280
|
600
|
80
|
|
Walnuts
|
840
|
300
|
120
|
180
|
Raisins
|
360
|
Unlimited
|
0
|
200
|
Since requirement of almond and peanut is quite less that availability, therefore, no effect on purchase plan will be seen. We require only 120 kg of almonds and 80 kg of peanuts. Supply is still more than demand.
After purchasing the 50 kg of walnut at the price of R 1100/kg, the average price of walnut becomes around R 877 /kg. After feeding the update price of walnut, we have to again run the solver. It was seen that no effect on total cost of the plan is seen. The reason is that we are already using almond in minimum way, we cannot use more at higher price.
Yes, the price is changed from 482000 to 525500, this because after increasing the constraint from 4000 to 4500, the amount of material required also changed accordingly, almond increased by 40 kg, Cashew is reduce by 15 kg, Peanut increased by 10 kg and walnut by 15 kg.
The new plan is as follows
Nuts
|
Cost of purchasing (Rand)
|
Material avaialable (Kg)
|
Delux mix
|
Companion mix
|
Almonds
|
1200
|
400
|
160
|
|
Cashew
|
1060
|
200
|
65
|
135
|
Peanuts
|
280
|
600
|
90
|
|
Walnuts
|
840
|
300
|
135
|
165
|
Raisins
|
360
|
Unlimited
|
0
|
200
|
If the price of peanut will increased by 40%, then its new price will be 280+280*0.4= 392. We have to place the new price in solver and solve accordingly. I think this effect is only due to unlimited stock of raisins, But raisins already have at optimum use. Therefore, it’s not affected the solution.
Bibliography
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Darst, R., 2008, Introduction to Linear Programming: Applications and Extensions. 4th ed. New York: Marcel Dekker.
Dunn, P, 2012, The Firm of the Future. 1st ed. 2012: Wiley.
Eiselt, H., 2008, Linear Programming and its Applications. 2nd Edition ed. Berlin: Springer.
Gulc, A, 2017, Models and Methods of Measuring the Quality of Logistic Service. Project, and Production Management, 255(264), pp. 1-10.
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