Programing Assignment Of C Language

199 Downloads 4 Pages / 806 Words

19-12-2015

Question 1:

Create a 2 dimensional array (10 by 10) that represents a maze: fill the maze with asterisks and then make a 'random' path of blanks from the lower left (0,0) element to the upper right (9,9) element. Create a maze running program that prints out the correct path. Your program should move square by square - if it finds and asterisk blocking its path, it searches the next adjacent square, etc. Submit 10 separate trials proving your program discovers the correct path. Each path MUST be random.

Answer 1:

#include

int safeZone(char m[10][10], int i, int j)
{
if(i >= 0 && i < 10 && j >= 0 && j < 10 && m[i][j] == ' ')
return 1;

return 0;
}
int check(char m[10][10], int i, int j, char solMaze[10][10])
{
if(i == 9 && j == 9)
{
solMaze[i][j] = ' ';
return 1;
}

if(safeZone(m, i, j) == 1)
{
solMaze[i][j] = ' ';

if (check(m, i+1, j, solMaze) == 1)
return 1;

if (check(m, i, j+1, solMaze) == 1)
return 1;

solMaze[i][j] = '*';
return 0;
}

return 0;
}

void printMazeSol(char solMaze[10][10])
{
int i, j;
printf("n|--------------------|");
for (i = 0; i < 10; i++)
{
printf("n|");
for (j = 0; j < 10; j++)
printf("%c ", solMaze[i][j]);
printf("|");
}
printf("n|--------------------|");
}

int mazeSolution(char m[10][10])
{
char solMaze[10][10] = { {'*', '*', '*', '*', '*', '*', '*', '*', '*', '*'},
{'*', '*', '*', '*', '*', '*', '*', '*', '*', '*'},
{'*', '*', '*', '*', '*', '*', '*', '*', '*', '*'},
{'*', '*', '*', '*', '*', '*', '*', '*', '*', '*'},
{'*', '*', '*', '*', '*', '*', '*', '*', '*', '*'},
{'*', '*', '*', '*', '*', '*', '*', '*', '*', '*'},
{'*', '*', '*', '*', '*', '*', '*', '*', '*', '*'},
{'*', '*', '*', '*', '*', '*', '*', '*', '*', '*'},
{'*', '*', '*', '*', '*', '*', '*', '*', '*', '*'},
{'*', '*', '*', '*', '*', '*', '*', '*', '*', '*'} };

if(check(m, 0, 0, solMaze) == 0)
{
printf("Solution doesn't exist");
return 0;
}

printMazeSol(solMaze);
return 1;
}

int main()
{
char m[10][10] = { {' ', '*', '*', '*', '*', '*', ' ', '*', '*', '*'},
{' ', '*', '*', '*', '*', '*', ' ', '*', '*', '*'},
{' ', ' ', ' ', '*', '*', '*', ' ', '*', '*', ' '},
{'*', '*', ' ', '*', '*', '*', ' ', '*', '*', ' '},
{'*', '*', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' '},
{'*', '*', ' ', '*', '*', '*', '*', '*', ' ', '*'},
{'*', '*', ' ', '*', '*', '*', '*', '*', ' ', '*'},
{'*', '*', ' ', '*', '*', '*', '*', '*', ' ', '*'},
{'*', '*', ' ', '*', '*', '*', '*', '*', ' ', ' '},
{'*', '*', ' ', '*', '*', '*', '*', '*', '*', ' '} };

mazeSolution(m);
getchar();
}

Output :

Question 2:

Write a program that outputs all numbers of n digits or less that meet the following constraint: let the number be X and let the number of digits of the number be called n with each digit being d1,d2,..,dn. The d1**n + d2**n + .. + dn**n = X. For example : 371 meets this constraint because 3**3 + 7**3 + 1**3 = 371 ! But 11 does NOT meet the constraint because 1**2 + 1**2 does not equal 11. Test your code for N = 30

Answer 2:

#include

void main()
{
long number, tempNum, result = 0, mul = 1;
int N, i, j;
int arrNum[50];

printf("Enter Number: ");
scanf("%d", &number);

N = 0;
tempNum = number;

while(tempNum > 0)
{
arrNum[N] = tempNum % 10;
tempNum = tempNum/10;
N = N + 1;
}

for(i=0; i<N; i++)
{
mul = 1;
for(j=0; j<N; j++)
{
mul = mul * arrNum[i];
}
result = result + mul;
}

if(result == number)
printf("n%d meets constraint", number);
else
printf("n%d does not meet constraint", number);

getch();
}

Output :

Enter number: 30

30 does not meet constraint

Enter number: 371

371 meet constraint

Enter number: 11

11 does not meet constraint.

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