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Using the same axes, draw graphs of the two equations from part (b). Use an x-scale from 0 to 50, and choose a y-scale that allows both lines to be seen over this range.
You may draw your graphs by hand, using squared paper, or use Graphplotter and send a printout with the rest of your TMA. Remember to label the lines with their equations.
(ii) What do the gradients and y-intercepts of these lines represent in terms of the situation being modelled?
(d) The lines representing the equations in part (b) intersect. Use your graphs to write down the approximate coordinates of the intersection point. How can the intersection point be interpreted in this model?
(e) Use algebra to solve the two simultaneous equations from part (b). Show each step of your working clearly.
(f) State which option gives the better deal, in terms of cost, for different numbers of teenagers attending.
3t = (7k/13) – 17
3t + 17 = (7k/13) – 17 + 17 (By adding 17 on both sides)
3t + 17 = (7k/13)
(3t+17)(13/7) =(7k/13)(13/7) (By multiplying 13/7 on both sides)
Hence, k = (13/7) (3t+17)
7k = (4k/3t) – 11t
7k + 11t = (4k/3t) – 11t + 11t (Adding 11t on both sides)
7k + 11t = (4k/3t)
Taking 7k to the RHS, we get
11t = (4k/3t) – 7k
11t = k [(4/3t) – 7] (Taking k common on RHS)
Hence, k = 11t[(4/3t) – 7]
Thus, k = (44/3)t2 – 77t
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