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Topics That We Cover

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Mathematics is a really interesting subject. It is how we humans study, define, and quantify nearly everything in existence. Math is the science of understanding quantities, distances, shapes, structures, relationships, and change. Research in the field leads mathematicians to explore, identify, and analyze patterns & processes with cold-hard logic, rigorous deductions, and unbiased reasoning. The results are always astounding and hugely beneficial in the grander scheme of things, as is evident from the ubiquity of mathematics in natural, formal, & applied sciences, engineering, humanities, management, and more. However, at the same time, the need for rigor, sharp logical reasoning abilities, problem-solving, and pattern recognition skills, coupled with the multitude of theorems, axioms, rules, and the like, make it a formidable challenge for any student. 

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A Look at Some Sample Solutions From Our Writers

Are we still having doubts? Well, then, here’s a simple linear regression solution from a higher/applied mathematics assignment crafted by our mathematics coursework experts.

Problem → 

Consider the following observation pairs (xi, yi)

(-1,6), (0,3), (1,2), (2,-1)

  1. Find the approximate regression line.

y’ = ß’0 + ß’1 xi

based on the observed data.

  1. For each xi, compute the fitted value of yi using

yi’ = ß’0 + ß’1 xi

  1. Find out the residuals

ei =  yi-  y’i

  1. Find R-squared (the coefficient of determination)


  1. We have

x’ = (-1+0+1+12)/4= 0.5

y’= (6+3+2-1)/4= 2.5

sxx= (-1-0.5)2 + (0-0.5)2 + (1-0.5)2 + (2-0.5)2 = 5 → this is the sample corrected sum of squares

sxy= (-1 - 0.5) (6 - 2.5) + (0 - 0.5)(3 - 2.5) + (1- 0.5)(2 - 2.5) + (2 - 0.5)(-1 - 0.25) = -11 →this is the sum of the products of differences between x values and differences between y values

So, we have 

ß’1   =  sxy / sxx = -11/5= -2.2

ß’0 = 2.5 – (-2.2)(0.5)= 3.6

  1. The fitted values are given by 

yi’ = 3.6 -2.2 xi

So, we have

y’1 = 5.8, y’2= 3.6, y’3= 1.4, y’4= -0.8

  1. The residuals obtained are as follows → 

e1 = y1 - y1’ = 6 - 5.8 = 0.2

e2 = y2 - y2’ = 3 - 3.6 = -0.6

e3 = y3 - y3’ =2 - 1.4 = 0.6

e4 = y4 - y4’ = -1 - (-0.8) = -0.2

  1. Finally, we find R-squared or the coefficient of determination as follows → 

syy = (6 - 2.5)2 + (3 - 2.5)2 + (2 - 2.5)2 +(-1 - 2.5)2 = 25

R2 = (-11)2/ (5*25) ~~ 0.968

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