1. If you have samples of and , in performing the pooled-variance test, how many degrees of freedom do you have? n = 181 n = 122 You have degrees of freedom.
2. Assume there is a sample of , with the sample mean and a sample standard deviation of , and there is an independent sample of from another population with a sample mean of and a sample standard deviation In performing the pooled-variance t test, how many degrees of freedom are there? n = 51 = 40X1 S = 41 n = 62 = 35X2 S = 62 There are degrees of freedom. 11/20/21, 11:45 AMHomework Assignment 10-Ahmad Cheema.
3. A recent study found that children who watched a commercial for potato chips featuring a celebrity endorser ate a mean of grams of potato chips as compared to a mean of grams for children who watched a commercial for an alternative food snack. Suppose that the sample standard deviation for the children who watched the celebrity-endorsed commercial was grams and the sample standard deviation for the children who watched the alternative food snack commercial was grams. Complete parts (a) through (d) below.62 40 25 52 21.4 12.8.
a. Assuming that the population variances are equal and , is there evidence that the mean amount of potato chips eaten was significantly higher for the children who watched the celebrity-endorsed commercial? α= 0.05.
Let population 1 be the weights of potato chips eaten by children who watched the celebrity-endorsed commercial and let population 2 be the weights of potato chips eaten by children who watched the alternative food snack commercial. What are the correct null and alternative hypotheses?
A. : 0H0 μ− μ1 2 ≥ : 0H1 μ− μ1 2 <
C. : 0H0 μ− μ1 2 ≤ : 0H1 μ− μ1 2 >
What is the test statistic? (Round to two decimal places as needed.)tSTAT=What is the corresponding p-value? p-value (Round to three decimal places as needed.)=What is the correct conclusion? A. There is evidence that the mean amount of potato chips eaten was significantly higher forDo not reject H0 sufficient.
B. There is evidence that the mean amount of potato chips eaten was significantly higher for childReject H0 insufficient.
C. There is evidence that the mean amount of potato chips eaten was significantly higher for childreReject H0 sufficient.
D. There is evidence that the mean amount of potato chips eaten was significantly higher foDo not reject H0 insufficient.
b. Assuming that the population variances are equal, construct a % confidence interval estimate of the difference between the mean amount of potato chips eaten by the children who watched the celebrity-endorsed commercial and children who watched the alternative food snack commercial.95 μ− μ1 2≤ μ− μ1 2 ≤(Type integers or decimals rounded to two decimal places as needed.).
c. Compare and discuss the results of (a) and (b). Choose the correct answer below.
A. The confidence interval in part (b) contains 0, which agrees with the decision made in part (a) to not reject the null hy.
B. The confidence interval in part (b) contains 0, which does not agree with the decision made in part (a) to reject the nu.
C. The confidence interval in part (b) does not contain 0, which agrees with the decision made in part (a) to reject the nu.
D. The confidence interval in part (b) does not contain 0, which does not agree with the decision made in part (a) to not.
E. The results cannot be compared, because part (a) is a one-tail test and part (b) is a confidence interval that is company.
d. Based on the results of (a) and (b), if you wanted to increase the consumption of this brand of potato chips, which commercial would you choose?
A. Choose the commercial with the celebrity endorser, since there is evidence that the mean amount of potato chips eat.
B. Choose the commercial without the celebrity endorser, since there is evidence that the mean amount of potato chips.
C. Choose the commercial without the celebrity endorser, since there is evidence that the mean amount of potato chips 11/20/21, 11:45 AMHomework Assignment 10-Ahmad Cheema.
D. Choose the commercial with the celebrity endorser, since there is evidence that the mean amount of potato chips.