1. Discuss and formulate the scenarios relevant for answering different questions
2. Demonstrate the interpretation of computer output to answer different questions
The use of information technology has affected the business process in all aspect. But use of information technology in Supply chain management, has totally chained the face of doing business, all the jargons like E-Commerce, EDI, ERP, Barcode, QR code, 3PL, all are only possible after the application of computer in supply chain management. Here we will see that how optimization can be done in limited resources with the help of computer application (Szpilko, 2017).
As given in the question, the first work to John smith is the analyses the data as given in question, the normal demand of Mech. wire is around 4276 unit, and average output is around 2400 unit/month, Therefore it clear that, we have to arrange all the resources to maximize the profit from the given output. The main difference in output and demand is due to the reason, that, the plant’s machine utilization is around 63%. By analysis and calculation we try to find, how we can optimize the available machine and resources in give condition. We will solve this problem with the help of excel solver in Microsoft Excel 2016 (Štefan Kudlá?, 2017).
The given situation, is suitable for linear programming, and this will be done by using excel solver, because, if we see the data we can analyze, LP is only the tools which can be used for this situation, The summary of data is as given below,
1 Next Month Order |
|
Product |
Units ordered |
W0075C |
1,400 |
W0033C |
250 |
W0005X |
1,510 |
W0007X |
1,116 |
2 Standard Cost |
||||
Product |
Material |
Labour |
Overhead |
Selling Price |
W0075C |
$33.00 |
$9.90 |
$23.10 |
$100.00 |
W0033C |
$25.00 |
$7.50 |
$17.50 |
$80.00 |
W0005X |
$35.00 |
$10.50 |
$24.50 |
$130.00 |
W0007X |
$75.00 |
$11.25 |
$64.75 |
$175.00 |
4 Plant Capacity |
|||
Drawing |
Extrusion |
Winding |
Packaging |
4,000 |
4,200 |
2,000 |
2,300 |
The above plant capacity data is full capacity data, but in question it is given that, the average machine utilization is 63% and 5% production is going to rework from winding, in this condition the utilized plant capacity is given as follows.
6 Capacity utilised(Actual) |
|||
2,520 |
2,646 |
1,197 |
1,449 |
And finally the bill of labor is given as
5 |
Bill of labour (hours/unit) |
|||
Product |
Drawing |
Extrusion |
Winding |
Packaging |
W0075C |
1 |
1 |
1 |
1 |
W0033C |
2 |
1 |
3 |
0 |
W0005X |
0 |
4 |
0 |
3 |
W0007X |
1 |
1 |
0 |
2 |
From the above situation we will formulate the linear programming which is as follows,
The actual profit /unit of wire can be taken as
Actual profit = Sell Price – (Material + labor + overhead)
The profit calculated for four different products is as follows,
W0075C |
W0033C |
W0005X |
W0007X |
$34.00 |
$30.00 |
$60.00 |
$25.00 |
Suppose, product W0075C is denoted as X1, similarly other product, W0033C, W0005X, W0007X is X2, X3, and X4 respectively, then our total profit will be calculated as
34x X1 + 30x X2 + 60x X3 + 25x X4 = Z, this will be objective which I have to maximize according to the above data.
The constraint can be given as
For plant capacity,
X1 + 2X2 + X4 2520 …………(i)
X1 + X2 + 4X3 + X4 2646 …..... (ii)
Formulating the Linear Programming
X1 + 3X2 1197 ……………..…(iii)
X1 + 3X3 + 2X4 1449 …………..(iv)
For demand capacity
X1 1400 …………………..(v)
X2 250 ……………………(vi)
X3 1510…………….……..(vii)
X4 1116, ……………..(viii)
Two more constrains is there because of commitment done by Vivian Napoli.
X1 150 ………………(ix)
X4 600 ………………(x)
Now to calculate the maximum capacity from the given data, we have to run the excel solver and put all the data as given in excel sheet.
Product |
W0075C |
W0033C |
W0005X |
W0007X |
|||
Units |
249 |
250 |
0 |
600 |
|||
Profit/Unit |
$34.00 |
$30.00 |
$60.00 |
$25.00 |
$30,966.00 |
||
Available constraints |
|||||||
W0075C orders |
1 |
0 |
0 |
0 |
249.00 |
<= |
1400 |
W0033C orders |
0 |
1 |
0 |
0 |
250.00 |
<= |
250 |
W0005X orders |
0 |
0 |
1 |
0 |
0.00 |
<= |
1510 |
W0007X orders |
0 |
0 |
0 |
1 |
600.00 |
<= |
1116 |
Drawing time |
1 |
2 |
0 |
1 |
1349.00 |
<= |
2520 |
Extrusion time |
1 |
1 |
4 |
1 |
1099.00 |
<= |
2646 |
Winding time |
1 |
3 |
0 |
0 |
999.00 |
<= |
1197 |
Packaging time |
1 |
0 |
3 |
2 |
1449.00 |
<= |
1449 |
Minimum W0075C |
1 |
0 |
0 |
0 |
249.00 |
>= |
150 |
Minimum W0007X |
0 |
0 |
0 |
1 |
600.00 |
>= |
600 |
The cell given in green is calculated maximum profit for given condition. The answer report and sensitivity analysis is given in excel sheet.
If we will see the utilisation of different section we will observe that, the % utilisation of different section i.e. Drawing, Extrusion, Winding and Packaging, we see that, it is around 53%, 41%, 83% and 100% for packaging, in this condition, it is clear that, almost half of the manpower in drawing section and extrusion section is unused, If by any means If we shift the manpower to winding, and packaging section, we can increase the output,
Suppose by shifting the manpower, we have increased the rated capacity of winding and packaging, in this condition we must put the maximum value of winding and packaging.
After running the solver but putting the value 2000 and 2300 for winding and packaging, the result is as follows
Product |
W0075C |
W0033C |
W0005X |
W0007X |
|||
Units |
1100 |
250 |
0 |
600 |
|||
Profit/Unit |
$34.00 |
$30.00 |
$60.00 |
$25.00 |
$59,900.00 |
||
Available constraints |
|||||||
W0075C orders |
1 |
0 |
0 |
0 |
1100.00 |
<= |
1400 |
W0033C orders |
0 |
1 |
0 |
0 |
250.00 |
<= |
250 |
W0005X orders |
0 |
0 |
1 |
0 |
0.00 |
<= |
1510 |
W0007X orders |
0 |
0 |
0 |
1 |
600.00 |
<= |
1116 |
Drawing time |
1 |
2 |
0 |
1 |
2200.00 |
<= |
2520 |
Extrusion time |
1 |
1 |
4 |
1 |
1950.00 |
<= |
2646 |
Winding time |
1 |
3 |
0 |
0 |
1850.00 |
<= |
2000 |
Packaging time |
1 |
0 |
3 |
2 |
2300.00 |
<= |
2300 |
Minimum W0075C |
1 |
0 |
0 |
0 |
1100.00 |
>= |
150 |
Minimum W0007X |
0 |
0 |
0 |
1 |
600.00 |
>= |
600 |
From the above solution it is clear that, if we shift the worker bay any means from drawing and extrusion department, the profit can be increase in such a way that, we can fulfil the required condition and earn maximum profit as profit $ 59,900.
The solution optimised solution suggest that, the product W0005X is not produced to maximise the profit, even profit margin for W0005X is highest, but it is also taking resources highest. The commitment done by Vivian Napoli can be easily fulfilled with the above condition,
Therefore, main problem is here is low utilisation of machine, and the mains constraints are packaging time, it is still clear from the above table is that if by any means we increase the packaging limit we can produce more with the given constraints, even if we increase the packaging by 3000, the almost all resources will be utilised and profit will be around $ 77000,
The best recommendation for john smith is that, it should stop producing W0005X, because resources are greatly utilised and any how increase the capacity of packaging department, so that maximum profit can be done without any further investment. The other recommendation is that the number of rejection should be reduced to, because this 5% will directly add to the profit margin.
Running Excel Solver
If we want to perform the sensitivity analysis for this problem, we have to develop table to identify the related information obtained from the sensitivity analysis, but sensitivity is not the report which can be presented directly to the meeting, we must change into lucrative form so that it can be presented.
The Sensitivity analysis of the above problem is given as follows,
Microsoft Excel 14.0 Sensitivity Report |
|||||||
Worksheet: [806856.xlsx]Sheet1 |
|||||||
Report Created: 30-09-2018 04:08:42 |
|||||||
Variable Cells |
|||||||
|
|
Final |
Reduced |
Objective |
Allowable |
Allowable |
|
Cell |
Name |
Value |
Cost |
Coefficient |
Increase |
Decrease |
|
$J$4 |
Units W0075C |
1100 |
0 |
34 |
1E+30 |
14 |
|
$K$4 |
Units W0033C |
250 |
0 |
30 |
1E+30 |
30 |
|
$L$4 |
Units W0005X |
0 |
-42 |
60 |
42 |
1E+30 |
|
$M$4 |
Units W0007X |
600 |
0 |
25 |
43 |
1E+30 |
|
Constraints |
|||||||
|
|
Final |
Shadow |
Constraint |
Allowable |
Allowable |
|
Cell |
Name |
Value |
Price |
R.H. Side |
Increase |
Decrease |
|
$N$10 |
W0075C orders |
1100 |
0 |
1400 |
1E+30 |
300 |
|
$N$11 |
W0033C orders |
250 |
30 |
250 |
50 |
250 |
|
$N$12 |
W0005X orders |
0 |
0 |
1510 |
1E+30 |
1510 |
|
$N$13 |
W0007X orders |
600 |
0 |
1116 |
1E+30 |
516 |
|
$N$14 |
Drawing time |
2200 |
0 |
2520 |
1E+30 |
320 |
|
$N$15 |
Extrusion time |
1950 |
0 |
2646 |
1E+30 |
696 |
|
$N$16 |
Winding time |
1850 |
0 |
2000 |
1E+30 |
150 |
|
$N$17 |
Packaging time |
2300 |
34 |
2300 |
150 |
950 |
|
$N$18 |
Minimum W0075C |
1100 |
0 |
150 |
950 |
1E+30 |
|
$N$19 |
Minimum W0007X |
600 |
-43 |
600 |
475 |
75 |
As per the report given above, we can analyses the situation; we can compare the production report with actual order report and can see that how much I have fulfilled the demand. In this way we can also show the way for management that which product is more necessary to produce.
Product |
Units ordered |
Order Produced |
Difference |
W0075C |
1,400 |
1100 |
300 |
W0033C |
250 |
250 |
0 |
W0005X |
1,510 |
0 |
1510 |
W0007X |
1,116 |
600 |
516 |
The total product produce is 1950 against the order 4276, in this production; we have fulfilled the demand of product W0033C. Additionally I have fulfilled the demand of Vivian Napoli. The production of W0005X is not taken into consideration by solver, even it is the product of maximum margin, but in terms of resources, this product is grabbing too many resources, therefore for maximum profit, the product W0005X is stopped.
Further looking into the Sensitivity analysis we can see that, we have to put the actual order and find the differences the cost is gone up by $42 and profit go by $ 102, but removing it cost is decrease by $42 and we get maximum profit after removing the W0005X.
Another aspect we can analyse is that, the utilisation of resources in each department.
Department |
Given Cap. |
Resources consumed |
Unutilised |
Drawing |
4000 |
2200 |
1800 |
Extrusion |
4200 |
1950 |
2250 |
Winding |
2000 |
1850 |
150 |
Packaging |
2300 |
2300 |
0 |
From the above table we can see that, the as per capacity of plant, the resources unitised are almost 50% for drawing and extrusion, and resources for winding is around 95%, but resources for packaging is fully utilised. Therefore, packaging is the bottleneck for the operation, we must exploit and subordinate the packaging section, so that, further resources can be utilized. For fully utilising the other resources, we must increase the packaging resource up to 3000 hr.
The limit report is also providing the same thing
Microsoft Excel 14.0 Limits Report |
|||||||||
Worksheet: [806856.xlsx]Sheet1 |
|||||||||
Report Created: 30-09-2018 04:08:42 |
|||||||||
|
Objective |
||||||||
Cell |
Name |
Value |
|||||||
$N$5 |
Profit/Unit |
? 59,900.00 |
|||||||
|
Variable |
Lower |
Objective |
Upper |
Objective |
||||
Cell |
Name |
Value |
Limit |
Result |
Limit |
Result |
|||
$J$4 |
Units W0075C |
1100 |
150 |
27600 |
1100 |
59900 |
|||
$K$4 |
Units W0033C |
250 |
0 |
52400 |
250 |
59900 |
|||
$L$4 |
Units W0005X |
0 |
0 |
59900 |
0 |
59900 |
|||
$M$4 |
Units W0007X |
600 |
600 |
59900 |
600 |
59900 |
The binding of constraints can also be visible in this section
Cell |
Name |
Cell Value |
Formula |
Status |
Slack |
$N$10 |
W0075C orders |
1100.00 |
$N$10<=$P$10 |
Not Binding |
300 |
$N$11 |
W0033C orders |
250.00 |
$N$11<=$P$11 |
Binding |
0 |
$N$12 |
W0005X orders |
0.00 |
$N$12<=$P$12 |
Not Binding |
1510 |
$N$13 |
W0007X orders |
600.00 |
$N$13<=$P$13 |
Not Binding |
516 |
$N$14 |
Drawing time |
2200.00 |
$N$14<=$P$14 |
Not Binding |
320 |
$N$15 |
Extrusion time |
1950.00 |
$N$15<=$P$15 |
Not Binding |
696 |
$N$16 |
Winding time |
1850.00 |
$N$16<=$P$16 |
Not Binding |
150 |
$N$17 |
Packaging time |
2300.00 |
$N$17<=$P$17 |
Binding |
0 |
$N$18 |
Minimum W0075C |
1100.00 |
$N$18>=$P$18 |
Not Binding |
950.00 |
$N$19 |
Minimum W0007X |
600.00 |
$N$19>=$P$19 |
Binding |
0.00 |
Here we can clearly see that the binding of data comes in W0033C order and packaging time. The order is as per demand, but packaging time is something which we can control.
As we have seen in the table and Sensitivity report above, it clear that, the drawing department is underutilized, in this condition we should not send the temporary labor to drawing department, rather we should send it to packaging department, In fact not need of temporary worker, here, we can utilize own worker of the company to manage the packaging department, One important information from the above reports is that, if we increase packaging hour by 1, out inherited profit will rise by $34, this packaging hour can go up to, 2500 hour without any additional resources. But if we further want to increase the profitability, we have to add some winding hour also, this will give leverage to increase the profit.
Sensitivity Analysis
Conclusion
The use of excel solver becomes very common for purpose of optimization problem. The main reason behind this is easy to use Solver tools given in Microsoft excel. The use of complex mathematical concept is history, when linear programming being solved by Simplex method or any other manual method, in 1950s when linear programing first used in US military, to find the low cost diet with highest nutrition value by Jerry Cornfield, it took 2 years to find the optimized value, but today with the use of computer we can dot in two hours or less.
This is the report which can be presented by John Smith to the management. There are various other possible permutation and combination of data by which we can analyses the result obtained from solver. If manpower is given for department, we can reschedule the entire problem in better optimization using this solver.
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